Rhombus formed with circumcenter and orthocenter
Source: Problem 7 of Russian Regional Olympiad 2011, grade 10
September 1, 2011
geometryrhombuscircumcircleangle bisectorgeometry proposed
Problem Statement
Points and are the respective midpoints of sides and of a non-isosceles acute triangle , is its circumscenter and is the orthocenter. Lines and intersect at , while lines and intersect at . is rhombus. Prove that points , and are collinear. (Author: L. Emelyanov)