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Rhombus formed with circumcenter and orthocenter

Source: Problem 7 of Russian Regional Olympiad 2011, grade 10

September 1, 2011
geometryrhombuscircumcircleangle bisectorgeometry proposed

Problem Statement

Points C0C_0 and B0B_0 are the respective midpoints of sides ABAB and ACAC of a non-isosceles acute triangle ABCABC, OO is its circumscenter and HH is the orthocenter. Lines BHBH and OC0OC_0 intersect at PP, while lines CHCH and OB0OB_0 intersect at QQ. OPHQOPHQ is rhombus. Prove that points AA, PP and QQ are collinear. (Author: L. Emelyanov)