MathDB
Junior Geometric Inequality with <BAC=60

Source: JBMO Shortlist 2013, G5

June 11, 2017
geometrygeometric inequality

Problem Statement

A circle passing through the midpoint MM of the side BCBC and the vertex AA of the triangle ABCABC intersects the segments ABAB and ACAC for the second time in the points PP and QQ, respectively. Prove that if BAC=60\angle BAC=60^{\circ}, then AP+AQ+PQ<AB+AC+12BCAP+AQ+PQ<AB+AC+\frac{1}{2} BC.