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China Mathematics Olympiads (National Round) 2008 Problem 1

Source:

November 28, 2010
geometrycircumcircleincentergeometric transformationreflectionperpendicular bisectorgeometry unsolved

Problem Statement

Suppose ABC\triangle ABC is scalene. OO is the circumcenter and AA' is a point on the extension of segment AOAO such that BAA=CAA\angle BA'A = \angle CA'A. Let point A1A_1 and A2A_2 be foot of perpendicular from AA' onto ABAB and ACAC. HAH_{A} is the foot of perpendicular from AA onto BCBC. Denote RAR_{A} to be the radius of circumcircle of HAA1A2\triangle H_{A}A_1A_2. Similiarly we can define RBR_{B} and RCR_{C}. Show that: 1RA+1RB+1RC=2R\frac{1}{R_{A}} + \frac{1}{R_{B}} + \frac{1}{R_{C}} = \frac{2}{R} where R is the radius of circumcircle of ABC\triangle ABC.