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Distance of Circles

Source: Iran 3rd round 2013 - final exam problem 2

September 25, 2014
geometrygeometric transformationhomothetygeometry unsolved

Problem Statement

We define the distance between two circles ω,ω\omega ,\omega 'by the length of the common external tangent of the circles and show it by d(ω,ω)d(\omega , \omega '). If two circles doesn't have a common external tangent then the distance between them is undefined. A point is also a circle with radius 00 and the distance between two cirlces can be zero. (a) Centroid. nn circles ω1,,ωn\omega_1,\dots, \omega_n are fixed on the plane. Prove that there exists a unique circle ω\overline \omega such that for each circle ω\omega on the plane the square of distance between ω\omega and ω\overline \omega minus the sum of squares of distances of ω\omega from each of the ωi\omega_is 1in1\leq i \leq n is constant, in other words:d(ω,ω)21ni=1nd(ωi,ω)2=constantd(\omega,\overline \omega)^2-\frac{1}{n}{\sum_{i=1}}^n d(\omega_i,\omega)^2= constant (b) Perpendicular Bisector. Suppose that the circle ω\omega has the same distance from ω1,ω2\omega_1,\omega_2. Consider ω3\omega_3 a circle tangent to both of the common external tangents of ω1,ω2\omega_1,\omega_2. Prove that the distance of ω\omega from centroid of ω1,ω2\omega_1 , \omega_2 is not more than the distance of ω\omega and ω3\omega_3. (If the distances are all defined) (c) Circumcentre. Let CC be the set of all circles that each of them has the same distance from fixed circles ω1,ω2,ω3\omega_1,\omega_2,\omega_3. Prove that there exists a point on the plane which is the external homothety center of each two elements of CC. (d) Regular Tetrahedron. Does there exist 4 circles on the plane which the distance between each two of them equals to 11?
Time allowed for this problem was 150 minutes.