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AK+BL+CM > AB+BC+CA

Source: Polish MO Recond Round 1983 p5

September 9, 2024
geometryGeometric Inequalities

Problem Statement

The bisectors of the angles CAB,ABC,BCA CAB, ABC, BCA of the triangle ABC ABC intersect the circle circumcribed around this triangle at points K,L,M K, L, M , respectively. Prove that AK+BL+CM>AB+BC+CA. AK+BL+CM > AB+BC+CA.
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