MathDB
Convex Hexagon

Source: Iran Third Round MO 1998, Exam 4, P2

October 31, 2010
inequalitiesgeometry unsolvedgeometry

Problem Statement

Let ABCDEFABCDEF be a convex hexagon such that AB=BC,CD=DEAB = BC, CD = DE and EF=FAEF = FA. Prove that ABBE+CDAD+EFCF32.\frac{AB}{BE}+\frac{CD}{AD}+\frac{EF}{CF} \geq \frac{3}{2}.