China Mathematics Olympiads (National Round) 2010 Problem 5
Source:
November 28, 2010
combinatorics unsolvedcombinatorics
Problem Statement
There is a deck of cards placed at every points and , where . We can do one of the following two operations at each step:
If there are more than 2 cards at some points , we can withdraw three cards from that deck and place one each at and . (Here and );
If there are more than or equal to cards at point , we can withdraw cards from that deck and place one each at .
Show that if the total number of cards is more than or equal to , we can make the number of cards at every points more than or equal to after finitely many steps.