MathDB
Nice geometry

Source: Serbian JBMO TST 2014, problem 3

March 29, 2016
geometryparallelogramcircumcircle

Problem Statement

Consider parallelogram ABCDABCD, with acute angle at AA, ACAC and BDBD intersect at EE. Circumscribed circle of triangle ACDACD intersects ABAB, BCBC and BDBD at KK, LL and PP (in that order). Then, circumscribed circle of triangle CELCEL intersects BDBD at MM. Prove that: KDKM=KLPCKD*KM=KL*PC