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number = sum of squares of divisors [Austria Regional Competition 2017, P4]

Source: Austrian Mathematics Olympiad Regional Competition (Qualifying Round) 2017, Problem 4

June 12, 2018
number theorySum of SquaresDivisorsDivisibility

Problem Statement

Determine all integers n2n \geq 2, satisfying n=a2+b2,n=a^2+b^2, where aa is the smallest divisor of nn different from 11 and bb is an arbitrary divisor of nn. Proposed by Walther Janous