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Another easy FE

Source: Iran MO 3rd round 2023 ,Day 2 P1

August 16, 2023
algebra

Problem Statement

For any function f:NNf:\mathbb{N}\to\mathbb{N} we define P(n)=f(1)f(2)...f(n)P(n)=f(1)f(2)...f(n) . Find all functions f:NNf:\mathbb{N}\to\mathbb{N} st for each a,ba,b : P(a)+P(b)a!+b!P(a)+P(b) | a! + b!