AMPN is inscriptable implies ABC is isosceles
Source: IberoAmerican 1987 Q2
November 12, 2010
geometrygeometric transformationreflectionconicshyperbolasymmetrytrigonometry
Problem Statement
In a triangle , and are the respective midpoints of the sides and , and is the point of intersection of and . Prove that, if it is possible to inscribe a circle in the quadrilateral , then the triangle is isosceles.