MathDB
a +\sqrt{ab}+ \sqrt[3]{abc} <= 4/3 (a + b + c)

Source: Dutch IMO TST 2016 day 2 p1

August 30, 2019
algebrainequalities

Problem Statement

Prove that for all positive reals a,b,ca, b,c we have: a+ab+abc343(a+b+c)a +\sqrt{ab}+ \sqrt[3]{abc}\le \frac43 (a + b + c)