MathDB
Weird but easy concurrency

Source: 2024 Taiwan TST Round 3 Independent Study 2-G

April 25, 2024
Taiwangeometry

Problem Statement

Let ABCABC be a triangle such that the angular bisector of ∠BAC\angle BAC, the BB-median and the perpendicular bisector of ABAB intersect at a single point XX. Let HH be the orthocenter of ABCABC. Show that ∠BXH=90∘\angle BXH = 90^{\circ}.
Proposed by usjl
Back to ProblemsView on AoPS