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1/(a^3 + 3b)+1/(b^3 + 3a)<=1/2 OLCOMA Costa Rica 2015 p5 day2

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September 30, 2021
algebrainequalities

Problem Statement

Let a,bR+a,b \in R^+ with ab=1ab = 1, prove that 1a3+3b+1b3+3a12.\frac{1}{a^3 + 3b}+\frac{1}{b^3 + 3a}\le \frac12.