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Today's Calculation Of Integral
2006 Today's Calculation Of Integral
92
Today's calculation of integral 92
Today's calculation of integral 92
Source: created by kunny
January 17, 2006
calculus
integration
limit
trigonometry
function
absolute value
calculus computations
Problem Statement
Evaluate
lim
n
→
∞
n
2
∫
−
1
n
1
n
(
2005
sin
x
+
2006
cos
x
)
∣
x
∣
d
x
.
\lim_{n\to\infty} n^2\int_{-\frac{1}{n}}^{\frac{1}{n}} (2005\sin x+2006\cos x)|x|dx.
lim
n
→
∞
n
2
∫
−
n
1
n
1
(
2005
sin
x
+
2006
cos
x
)
∣
x
∣
d
x
.
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