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Putnam
1999 Putnam
4
Putnam 1999 A4
Putnam 1999 A4
Source:
December 22, 2012
Putnam
calculus
derivative
college contests
Problem Statement
Sum the series
∑
m
=
1
∞
∑
n
=
1
∞
m
2
n
3
m
(
n
3
m
+
m
3
n
)
.
\sum_{m=1}^\infty\sum_{n=1}^\infty\dfrac{m^2n}{3^m(n3^m+m3^n)}.
m
=
1
∑
∞
n
=
1
∑
∞
3
m
(
n
3
m
+
m
3
n
)
m
2
n
.
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