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Divisible by 2^2000

Source: Chinese Mathematical Olympiad 1998 Problem 4

August 22, 2013
number theory unsolvednumber theory

Problem Statement

Find all natural numbers n>3n>3, such that 220002^{2000} is divisible by 1+Cn1+Cn2+Cn31+C^1_n+C^2_n+C^3_n.
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