MathDB
Two inequality mixed together

Source: 2018 Thailand October Camp 2.2

February 19, 2022
inequalities

Problem Statement

Let a,b,c(0,43)a,b,c\in(0,\frac{4}{3}) and a+b+c=3a + b + c = 3. Prove that 4abc(a+b)(a+c)+(a+b)2+(a+c)2(a+b)+(a+c)cyc1a2(3b+3c5).\frac{4abc}{(a+b)(a+c)}+\frac{(a+b)^2+(a+c)^2}{(a+b)+(a+c)}\leq\sum_{cyc}\frac{1}{a^2(3b+3c-5)}.