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2
KMO #2 (Grade 10) [floor function equation]
KMO #2 (Grade 10) [floor function equation]
Source:
March 13, 2011
function
floor function
algebra proposed
algebra
Problem Statement
Find all solutions to the equation:
(
⌊
x
+
7
3
⌋
)
2
−
⌊
x
−
9
4
⌋
=
16
\left(\left\lfloor x+\frac{7}{3} \right\rfloor \right)^2-\left\lfloor x-\frac{9}{4} \right\rfloor = 16
(
⌊
x
+
3
7
⌋
)
2
−
⌊
x
−
4
9
⌋
=
16
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