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Tuymaada Olympiad
1998 Tuymaada Olympiad
2
2
Part of
1998 Tuymaada Olympiad
Problems
(1)
(x^3-1000)^{1/2}=(x^2+100)^{1/3}
Source: Tuymaada 1998 p2
4/28/2019
Solve the equation
(
x
3
ā
1000
)
1
/
2
=
(
x
2
+
100
)
1
/
3
(x^3-1000)^{1/2}=(x^2+100)^{1/3}
(
x
3
ā
1000
)
1/2
=
(
x
2
+
100
)
1/3
algebra
radical
equation