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Tuymaada Olympiad
1998 Tuymaada Olympiad
2
(x^3-1000)^{1/2}=(x^2+100)^{1/3}
(x^3-1000)^{1/2}=(x^2+100)^{1/3}
Source: Tuymaada 1998 p2
April 28, 2019
algebra
radical
equation
Problem Statement
Solve the equation
(
x
3
ā
1000
)
1
/
2
=
(
x
2
+
100
)
1
/
3
(x^3-1000)^{1/2}=(x^2+100)^{1/3}
(
x
3
ā
1000
)
1/2
=
(
x
2
+
100
)
1/3
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