MathDB

2001 Chile Classification NMO Seniors

Part of Chile Classification NMO

Subcontests

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2001 Chile Classification / Qualifying NMO Seniors XIII

p1. All positive fractions less than one are considered, whose denominator is 20012001 and whose numerator is a number that has no common divisors with 20012001. Calculate the sum of these fractions.
p2. Triangle ABCABC is right isosceles. The figure below shows two basic ways to inscribe a square in it. Prove that the square ADEFADEF has a greater area than the square GHIJGHIJ. https://cdn.artofproblemsolving.com/attachments/9/3/84d0cda6e109aaf01fb2f3de4d1933f0f16f82.jpg
p3. Given 99 people, show that there exists a value of nn such that with people you can form nn groups of a 33, so that each pair of people is in exactly one of these groups and show a corresponding conformation of these groups. If the same number of groups must be formed, but of 66 people each and with the condition that each pair is in exactly kk groups, determine if there is a value of kk that makes it possible for the problem to have a solution and, if affirmative, display a corresponding formation.
p4. Let ABCDABCD be a parallelogram. Side ABAB is extended to a point EE, such that BE=BCBE = BC and the side ADAD is extended to a point FF, such that DF=DCDF = DC. \bullet Prove that points EE, CC, and FF are collinear. \bullet Prove that the perpendicular to line AEAE at point EE, the perpendicular to line AFAF at point FF, the bisector of the angle EAFEAF and the perpendicular to the diagonal BDBD by the vertex CC are all concurrent at a point GG. https://cdn.artofproblemsolving.com/attachments/c/1/e0d585f30c4c9ca274e1ce1599128e3e21a08c.png
p5. Consider two positive integers xx and yy that satisfy the relation 3x2+x=4y2+y3x^2 + x = 4y^2 + y. Prove that the numbers (xy)(x-y), (3x+3y+1)(3x + 3y + 1), (4x+4y+1)(4x + 4y + 1) are three perfect squares.
p6. Let ABCDABCD be an quadrilateral inscribed in a circle of radius r, and let E be the point where its diagonals intersect. \bullet Prove if the diagonals are perpendicular to each other, then AE2+BE2+CE2+DE2=4r2AE^2 + BE^2 + CE^2 + DE^2 = 4r^2. \bullet If the previous relation is fulfilled, are the diagonals of the quadrilateral necessarily perpendicular?
p7 On a rectangular board with mm rows and n columns, place in each of the squares mnmn a 11 or a 00, so that the numbers in each add the same amount ff and those in each column, the same amount cc. Show that a necessary and sufficient condition for this assignment to be possible is that mf=ncmf = nc.
PS. Seniors p2, part of p6, were posted also as [url=https://artofproblemsolving.com/community/c4h2689068p23335606]Juniors variation p2, p6.