3
Part of 2007 China National Olympiad
Problems(2)
China Mathematics Olympiads (National Round) 2007 Problem 6
Source:
11/28/2010
Find a number such that for any numbers, not necessarily distinct, , there exists 9 numbers and such that is a multiple of 9.
pigeonhole principlenumber theory unsolvednumber theory
China Mathematics Olympiads (National Round) 2007 Problem 3
Source:
11/28/2010
Let be 11 pairwise distinct positive integer with sum less than 2007. Let S be the sequence of . Define an operation to be 22 consecutive applications of the following steps on the sequence : on -th step, choose a number from the sequense at random, say . If , replace with ; if , replace with . If the result of operation on the sequence is an odd permutation of , it is an odd operation; if the result of operation on the sequence is an even permutation of , it is an even operation. Which is larger, the number of odd operation or the number of even permutation? And by how many?Here is an even permutation of if the product is positive, and an odd one otherwise.
combinatorics unsolvedcombinatorics