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Contests
National and Regional Contests
Costa Rica Contests
Costa Rica - Final Round
2013 Costa Rica - Final Round
2013 Costa Rica - Final Round
Part of
Costa Rica - Final Round
Subcontests
(14)
G3
1
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SM // CL wanted, rectangle ABCD with <DAC=60^o
Let
A
B
C
D
ABCD
A
BC
D
be a rectangle with center
O
O
O
such that
∠
D
A
C
=
6
0
o
\angle DAC = 60^o
∠
D
A
C
=
6
0
o
. Bisector of
∠
D
A
C
\angle DAC
∠
D
A
C
cuts a
D
C
DC
D
C
at
S
S
S
,
O
S
OS
OS
and
A
D
AD
A
D
intersect at
L
L
L
,
B
L
BL
B
L
and
A
C
AC
A
C
intersect at
M
M
M
. Prove that
S
M
∥
C
L
SM \parallel CL
SM
∥
C
L
.
G2
1
Hide problems
<ABP=<ACP if BAP=<CAQ and PBQC parallelogram
Consider the triangle
A
B
C
ABC
A
BC
. Let
P
,
Q
P, Q
P
,
Q
inside the angle
A
A
A
such that
∠
B
A
P
=
∠
C
A
Q
\angle BAP=\angle CAQ
∠
B
A
P
=
∠
C
A
Q
and
P
B
Q
C
PBQC
PBQC
is a parallelogram. Show that
∠
A
B
P
=
∠
A
C
P
.
\angle ABP=\angle ACP.
∠
A
BP
=
∠
A
CP
.
F2
1
Hide problems
f(x) (f (\sqrt[3]((2+x) /(2-x) ) ^2= x^3/ 4
Find all functions
f
:
R
−
{
0
,
2
}
→
R
f:R -\{0,2\} \to R
f
:
R
−
{
0
,
2
}
→
R
that satisfy for all
x
≠
0
,
2
x \ne 0,2
x
=
0
,
2
f
(
x
)
⋅
(
f
(
2
+
x
2
−
x
3
)
)
2
=
x
3
4
f(x) \cdot \left(f\left(\sqrt[3]{\frac{2+x}{2-x}}\right) \right)^2=\frac{x^3}{4}
f
(
x
)
⋅
(
f
(
3
2
−
x
2
+
x
)
)
2
=
4
x
3
F1
1
Hide problems
f (x + y) = (f (x))^{ 2013} + f (y)
Find all functions
f
:
R
→
R
f: R\to R
f
:
R
→
R
such that for all real numbers
x
,
y
x, y
x
,
y
is satisfied that
f
(
x
+
y
)
=
(
f
(
x
)
)
2013
+
f
(
y
)
.
f (x + y) = (f (x))^{ 2013} + f (y).
f
(
x
+
y
)
=
(
f
(
x
)
)
2013
+
f
(
y
)
.
LRP2
1
Hide problems
probability even a^b + c generates as a result of an even number
From a set containing
6
6
6
positive and consecutive integers they are extracted, randomly and with replacement, three numbers
a
,
b
,
c
a, b, c
a
,
b
,
c
. Determine the probability that even
a
b
+
c
a^b + c
a
b
+
c
generates as a result .
LRP1
1
Hide problems
numbers on faces of a pyramid with base 2013-gon
Consider a pyramid whose base is a
2013
2013
2013
-sided polygon. On each face of the pyramid the number
0
0
0
is written. The following operation is carried out: a vertex is chosen from the pyramid and add or subtract
1
1
1
from all the faces that contain that vertex. It's possible, after repeating a finite number of times the previous procedure, that all the faces of the pyramid have the number
1
1
1
written?
N1
1
Hide problems
diopantine a^p - b^p = 2013
Find all triples
(
a
,
b
,
p
)
(a, b, p)
(
a
,
b
,
p
)
of positive integers, where
p
p
p
is a prime number, such that
a
p
−
b
p
=
2013
a^p - b^p = 2013
a
p
−
b
p
=
2013
.
A1
1
Hide problems
6(x^3+y^3+z^3)^2<=(x^2+y^2+z^2)^3 OLCOMA Costa Rica Finals 2013 SL A1 d1
Let the real numbers
x
,
y
,
z
x, y, z
x
,
y
,
z
be such that
x
+
y
+
z
=
0
x + y + z = 0
x
+
y
+
z
=
0
. Prove that
6
(
x
3
+
y
3
+
z
3
)
2
≤
(
x
2
+
y
2
+
z
2
)
3
.
6(x^3 + y^3 + z^3)^2 \le (x^2 + y^2 + z^2)^3.
6
(
x
3
+
y
3
+
z
3
)
2
≤
(
x
2
+
y
2
+
z
2
)
3
.
4
1
Hide problems
2 hats, each looking for their own number, one minute timer
Antonio and Beltran have impeccable logical reasoning, they put on a hat with a integer between
0
0
0
and
19
19
19
(including both) so that each of them sees the number that has the other (but cannot see his own number), and they must try to guess the number that have on their hat. They have a timer that a bell rings every minute and the moment it rings. This is when they must say if they know the number on their hat. A third person tells them: ''the sum of the numbers is
6
6
6
or
11
11
11
or
19
19
19
''. At that moment it begins to run time. After a minute the bell rings and neither of them says anything. The second minute passes , the doorbell rings and neither of us says anything. Time continues to pass and when the bell rings for the tenth time Antonio says that he already knows what is his number. Just determine the number each has in his hat.
6
1
Hide problems
b/a= 6 if b is divisible by a, overline{ab}= (a + b)^2
Let
a
a
a
and
b
b
b
be positive integers (of one or more digits) such that
b
b
b
is divisible by
a
a
a
, and if we write
a
a
a
and
b
b
b
, one after the other in this order, we get the number
(
a
+
b
)
2
(a + b)^2
(
a
+
b
)
2
. Prove that
b
a
=
6
\frac{b}{a}= 6
a
b
=
6
.
5
1
Hide problems
5-degree polynomial, divisible by x^2-x+1, coefficients in1-8
Determine the number of polynomials of degree
5
5
5
with different coefficients in the set
{
1
,
2
,
3
,
4
,
5
,
6
,
7
,
8
}
\{1, 2, 3, 4, 5, 6, 7, 8\}
{
1
,
2
,
3
,
4
,
5
,
6
,
7
,
8
}
such that they are divisible by
x
2
−
x
+
1
x^2-x + 1
x
2
−
x
+
1
. Justify your answer.
2
1
Hide problems
find even = sum of odd composite positive integers
Determine all even positive integers that can be written as the sum of odd composite positive integers.
1
1
Hide problems
3x3 system x^2 = y + z, y^2 = x + z, z^2 = x + y
Determine and justify all solutions
(
x
,
y
,
z
)
(x,y, z)
(
x
,
y
,
z
)
of the system of equations:
x
2
=
y
+
z
x^2 = y + z
x
2
=
y
+
z
y
2
=
x
+
z
y^2 = x + z
y
2
=
x
+
z
z
2
=
x
+
y
z^2 = x + y
z
2
=
x
+
y
3
1
Hide problems
concyclic wanted, starting with right triangle
Let
A
B
C
ABC
A
BC
be a triangle, right-angled at point
A
A
A
and with
A
B
>
A
C
AB>AC
A
B
>
A
C
. The tangent through
A
A
A
of the circumcircle
G
G
G
of
A
B
C
ABC
A
BC
cuts
B
C
BC
BC
at
D
D
D
.
E
E
E
is the reflection of
A
A
A
over line
B
C
BC
BC
.
X
X
X
is the foot of the perpendicular from
A
A
A
over
B
E
BE
BE
.
Y
Y
Y
is the midpoint of
A
X
AX
A
X
,
Z
Z
Z
is the intersection of
B
Y
BY
B
Y
and
G
G
G
other than
B
B
B
, and
F
F
F
is the intersection of
A
E
AE
A
E
and
B
C
BC
BC
. Prove
D
,
Z
,
F
,
E
D, Z, F, E
D
,
Z
,
F
,
E
are concyclic.