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diopantine a^p - b^p = 2013

Source: OLCOMA Costa Rica National Olympiad, Final Round, 2013 Shortlist N1 day1

September 26, 2021
number theoryDiophantine equationdiophantine

Problem Statement

Find all triples (a,b,p)(a, b, p) of positive integers, where pp is a prime number, such that apāˆ’bp=2013a^p - b^p = 2013.
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