4
Part of 2001 Bundeswettbewerb Mathematik
Problems(2)
Segment AB has no common point with the square R
Source: Germany Bundeswettbewerb Mathematik 2001, Round 2, Problem 4
1/17/2004
A square of sidelength lies inside a square of sidelength . Prove that: One can always find two points and on the perimeter of such that the segment has no common point with the square , and the length of this segment is greater than .
geometryperimeterrotationalgebrafunctiondomaingeometry unsolved
Nb. of divisors whose dec. representations ends with 1 or 9
Source: Germany Bundeswettbewerb Mathematik 2001, Round 1, Problem 4
2/1/2009
Prove: For each positive integer is the number of divisors whose decimal representations ends with a 1 or 9 not less than the number of divisors whose decimal representations ends with 3 or 7.
number theoryprime factorizationprime numbersnumber theory unsolved