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Problems
Contests
National and Regional Contests
Germany Contests
German National Olympiad
2006 German National Olympiad
2006 German National Olympiad
Part of
German National Olympiad
Subcontests
(6)
4
1
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A point far, far away...
Let
D
D
D
be a point inside a triangle
A
B
C
ABC
A
BC
such that
∣
A
C
∣
−
∣
A
D
∣
≥
1
|AC| -|AD| \geq 1
∣
A
C
∣
−
∣
A
D
∣
≥
1
and
∣
B
C
∣
−
∣
B
D
∣
≥
1.
|BC|- |BD| \geq 1.
∣
BC
∣
−
∣
B
D
∣
≥
1.
Prove that for any point
E
E
E
on the segment
A
B
AB
A
B
, we have
∣
E
C
∣
−
∣
E
D
∣
≥
1.
|EC| -|ED| \geq 1.
∣
EC
∣
−
∣
E
D
∣
≥
1.
6
1
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A Geometry problem
Let a circle through
B
B
B
and
C
C
C
of a triangle
A
B
C
ABC
A
BC
intersect
A
B
AB
A
B
and
A
C
AC
A
C
in
Y
Y
Y
and
Z
Z
Z
, respectively. Let
P
P
P
be the intersection of
B
Z
BZ
BZ
and
C
Y
CY
C
Y
, and let
X
X
X
be the intersection of
A
P
AP
A
P
and
B
C
BC
BC
. Let
M
M
M
be the point that is distinct from
X
X
X
and on the intersection of the circumcircle of the triangle
X
Y
Z
XYZ
X
Y
Z
with
B
C
BC
BC
. Prove that
M
M
M
is the midpoint of
B
C
BC
BC
2
1
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Max value for min distance
Five points are on the surface of of a sphere of radius
1
1
1
. Let
a
min
a_{\text{min}}
a
min
denote the smallest distance (measured along a straight line in space) between any two of these points. What is the maximum value for
a
min
a_{\text{min}}
a
min
, taken over all arrangements of the five points?
5
1
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Not so standard inequality involving absolute values, roots
Let
x
≠
0
x \neq 0
x
=
0
be a real number satisfying
a
x
2
+
b
x
+
c
=
0
ax^2+bx+c=0
a
x
2
+
b
x
+
c
=
0
with
a
,
b
,
c
∈
Z
a,b,c \in \mathbb{Z}
a
,
b
,
c
∈
Z
obeying
∣
a
∣
+
∣
b
∣
+
∣
c
∣
>
1
|a|+|b|+|c| > 1
∣
a
∣
+
∣
b
∣
+
∣
c
∣
>
1
. Then prove
∣
x
∣
≥
1
∣
a
∣
+
∣
b
∣
+
∣
c
∣
−
1
.
|x| \geq \frac{1}{|a|+|b|+|c|-1}.
∣
x
∣
≥
∣
a
∣
+
∣
b
∣
+
∣
c
∣
−
1
1
.
3
1
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Germany National Olympiad
For which positive integer n can you color the numbers 1,2...2n with n colors, such that every color is used twice and the numbers 1,2,3...n occur as difference of two numbers of the same color exatly once.
1
1
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101...101
Find all
n
∈
Z
+
n\in \mathbb Z^+
n
∈
Z
+
, so that
z
n
=
101
…
101
⏟
2
n
+
1
digits
z_n = \underbrace{ 101\dots101}_{2n+1 \text{ digits} }
z
n
=
2
n
+
1
digits
101
…
101
is prime.