Give are the integers a1=11,a2=1111,a3=111111,...,an=1111...111( with 2n digits) with n>8 .
Let qi=11ai,i=1,2,3,...,n the remainder of the division of ai by11 .
Prove that the sum of nine consecutive quotients: si=qi+qi+1+qi+2+...+qi+8 is a multiple of 9 for any i=1,2,3,...,(n−8) number theoryconsecutiveSummultiple