Problems(1)
In a conference, mathematicians from 11 different countries participate and they have integer-valued ages between 27 and 33 years (including 27 and 33). There is at least one mathematician from each country, and there is at least one mathematician of each possible age between 27 and 33. Show that we can find at least five mathematicians m1,…,m5 such that for any i∈{1,…,5} there are more mathematicians in the conference having the same age as mi than those having the same nationality as mi.Proposed by S. Muralidharan combinatorics