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Conference of mathematicians

Source: India IMOTC Practice Test 1 Problem 3

May 31, 2024
combinatorics

Problem Statement

In a conference, mathematicians from 1111 different countries participate and they have integer-valued ages between 2727 and 3333 years (including 2727 and 3333). There is at least one mathematician from each country, and there is at least one mathematician of each possible age between 2727 and 3333. Show that we can find at least five mathematicians m1,,m5m_1, \ldots, m_5 such that for any i{1,,5}i \in \{1, \ldots, 5 \} there are more mathematicians in the conference having the same age as mim_i than those having the same nationality as mim_i.
Proposed by S. Muralidharan