2
Part of 2021 Iran RMM TST
Problems(3)
easy function on Tst
Source: Iranian RMM TST 2021 Day1 P2
4/16/2021
Let satisfying . Prove that if for all , , then for all Proposed by Navid Safaei
functionalgebra
GGG4 geometry in a Tst
Source: Iranian RMM TST 2021 Day2 P2
4/16/2021
Let be a triangle with and with incenter . Let be the midpoint of , and let be the midpoint of the circular arc . Lines through parallel to meet at and , respectively, and meet and at and , respectively. Show that lies on the radical axis of the circumcircles of triangles and .Proposed by Andrew Wu
geometryincenterpower of a pointradical axiscircumcircle
putting queen's on the chess board.
Source: Iranian RMM TST 2021 Day3 P2
4/16/2021
In a chess board we call a group of queens independant if no two are threatening each other. In an by grid, we put exaxctly one queen in each cell ofa greed. Let us denote by the minimum number of independant groups that hteir union contains all the queens. Let be a positive integer, prove that Proposed by Alireza Haghi
combinatoricschess