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143

Part of 2006 Today's Calculation Of Integral

Problems(1)

Today's calculation of Integral 143

Source: Tokyo University of Fisheries entrance exam 1971

8/27/2006
Evaluate ∫0π21−sin⁡2x(1+sin⁡2x)2 dx.\int_{0}^{\frac{\pi}{2}}\frac{1-\sin 2x}{(1+\sin 2x)^{2}}\ dx.
calculusintegrationtrigonometrycalculus computations