MathDB
Today's calculation of Integral 143

Source: Tokyo University of Fisheries entrance exam 1971

August 27, 2006
calculusintegrationtrigonometrycalculus computations

Problem Statement

Evaluate ∫0π21−sin⁡2x(1+sin⁡2x)2 dx.\int_{0}^{\frac{\pi}{2}}\frac{1-\sin 2x}{(1+\sin 2x)^{2}}\ dx.
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