MathDB
Problems
Contests
National and Regional Contests
Japan Contests
Today's Calculation Of Integral
2006 Today's Calculation Of Integral
96
96
Part of
2006 Today's Calculation Of Integral
Problems
(1)
Today's calculation of integral 96
Source: Japan Women's University entrance exam 2006
2/5/2006
For
a
≥
0
,
a\geq 0,
a
≥
0
,
find the minimum value of
∫
−
2
1
∣
x
2
+
2
a
x
∣
d
x
.
\int_{-2}^1 |x^2+2ax| dx.
∫
−
2
1
∣
x
2
+
2
a
x
∣
d
x
.
calculus
integration
function
calculus computations