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Today's calculation of integral 96

Source: Japan Women's University entrance exam 2006

February 5, 2006
calculusintegrationfunctioncalculus computations

Problem Statement

For a≥0,a\geq 0, find the minimum value of ∫−21∣x2+2ax∣dx.\int_{-2}^1 |x^2+2ax| dx.
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