MathDB

2006.7

Part of Swiss NMO - geometry

Problems(1)

CD + DA = AB if ABCD cyclic, <ABC=60^o, BC=CD

Source: Switzerland - Swiss MO 2006 p7

7/18/2020
Let ABCDABCD be a cyclic quadrilateral with ∠ABC=60o\angle ABC = 60^o and ∣BC∣=∣CD∣| BC | = | CD |. Prove that ∣CD∣+∣DA∣=∣AB∣|CD| + |DA| = |AB|
geometryequal segmentscyclic quadrilateral