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CD + DA = AB if ABCD cyclic, <ABC=60^o, BC=CD

Source: Switzerland - Swiss MO 2006 p7

July 18, 2020
geometryequal segmentscyclic quadrilateral

Problem Statement

Let ABCDABCD be a cyclic quadrilateral with ∠ABC=60o\angle ABC = 60^o and ∣BC∣=∣CD∣| BC | = | CD |. Prove that ∣CD∣+∣DA∣=∣AB∣|CD| + |DA| = |AB|
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