MathDB

2017.10.4

Part of Kharkiv City MO Seniors - geometry

Problems(1)

<DAB=90^o,<ADC = < BAM => < ADB = CAM (Kharkiv City X 2017- Ukr)

Source:

3/19/2020
In the quadrangle ABCDABCD, the angle at the vertex AA is right. Point MM is the midpoint of the side BCBC. It turned out that ∠ADC=∠BAM\angle ADC = \angle BAM. Prove that ∠ADB=∠CAM\angle ADB = \angle CAM.
geometryanglesmidpointKharkiv