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<DAB=90^o,<ADC = < BAM => < ADB = CAM (Kharkiv City X 2017- Ukr)

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March 19, 2020
geometryanglesmidpointKharkiv

Problem Statement

In the quadrangle ABCDABCD, the angle at the vertex AA is right. Point MM is the midpoint of the side BCBC. It turned out that ADC=BAM\angle ADC = \angle BAM. Prove that ADB=CAM\angle ADB = \angle CAM.