Let G be an abelian group, 0≤ε<1 and f:G→Rn a function that satisfies the inequality.
∣∣f(x+y)−f(x)−f(y)∣∣≤ε∣∣f(y)∣∣(x,y)∈G2
Prove that there is an additive function A:G→Rn and a continuous function φ:A(G)→Rn such that f=φ∘A. group theoryEuclidean spacefunction