MathDB
Today's calculation of Integral 841

Source: 2012 Kobe University entrance exam・Science

August 2, 2012
calculusintegrationfunctiontrigonometrycalculus computations

Problem Statement

Find ∫0xdt1+t2+∫01xdt1+t2 (x>0).\int_0^x \frac{dt}{1+t^2}+\int_0^{\frac{1}{x}} \frac{dt}{1+t^2}\ (x>0).
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