MathDB
x^2- yz = |y-z| +1, y^2 - zx = |z-x| +1, z^2 -xy = |x-y| + 1

Source: 2021 Dutch BxMO TST p2

December 28, 2021
system of equationsSystemalgebra

Problem Statement

Find all triplets (x,y,z)(x, y, z) of real numbers for which {x2yz=yz+1y2zx=zx+1z2xy=xy+1\begin{cases}x^2- yz = |y-z| +1 \\ y^2 - zx = |z-x| +1 \\ z^2 -xy = |x-y| + 1 \end{cases}