Sum 1989 pos. real numbers greather than 2/995
Source: IMO Longlist 1989, Problem 26
September 18, 2008
algebra unsolvedalgebra
Problem Statement
Let be positive real numbers such that the equations
x_{r\minus{}1} \minus{} 2x_r \plus{} x_{r\plus{}1} \plus{} b_rx_r \equal{} 0 (1 \leq r \leq 1989)
have a solution with x_0 \equal{} x_{1989} \equal{} 0 but not all of are equal to zero. Prove that
\sum^{1989}_{k\equal{}1} b_k \geq \frac{2}{995}.